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Question #41680

Difficulty: 8/10 | 🟢 Free

The Question

Let RR be the region in the xyxy-plane consisting of all points (x,y)(x, y) that satisfy the conditions: x2+y2≤36x^2 + y^2 \le 36 ∑k=272x−2k−1(x−k)2(x−k−1)2≥0\sum_{k=2}^{7} \frac{2x - 2k - 1}{(x-k)^2 (x-k-1)^2} \ge 0 Let MM be the supremum of the objective function Z=x+yZ = x + y over the region RR. Find the value of MM.

Options

  • A.

    5+115 + \sqrt{11}

  • B.

    626\sqrt{2}

  • C.

    2+422 + 4\sqrt{2}

  • D.

    66

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Objective Function Gradient|The Telescopic Series Trap|Even Multiplicity Roots

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle telescopic series combined with rational inequalities, specifically targeting the 'Wavy Curve' trap for even-multiplicity roots.

Students must first recognize the general term simplifies to a difference of squares, allowing the series to telescope.

The lethal collision occurs when solving the resulting inequality 12(x−5)(x−2)2(x−8)2≥0\frac{12(x-5)}{(x-2)^2(x-8)^2} \ge 0.

A common mistake is treating the roots of the denominator (x=2,8x=2, 8) as points where the sign changes (odd multiplicity), leading to an incorrect feasible region of x∈(2,5)x \in (2, 5).

In this fake region, the objective function x+yx+y reaches its unconstrained maximum of 626\sqrt{2}.

However, correctly identifying that even-multiplicity roots do not change the sign reveals the true feasible region is x∈(5,6)x \in (5, 6), where the function is strictly decreasing, making the supremum 5+115+\sqrt{11}.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Programming - Class 12
ConceptObjective Function Gradient
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree