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Question #41699

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all ordered pairs (x,y)(x, y) of real numbers satisfying the system of equations: (8[x])+(8[y])=84\binom{8}{[x]} + \binom{8}{[y]} = 84 [x+y]=[x]+[y][x + y] = [x] + [y] x−y=[x]−[y]−15x - y = [x] - [y] - \frac{1}{5} 2x+3y=2[x]+3[y]+41102x + 3y = 2[x] + 3[y] + \frac{41}{10} where [t][t] denotes the greatest integer less than or equal to tt. Find the number of elements in SS.

Options

  • A.

    0

  • B.

    4

  • C.

    8

  • D.

    16

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Inconsistency Detection|Integral Part and Fractional Part|Step Function Discontinuities

Why This Question Is Tricky

Common Mistakes

This question tests the candidate's ability to detect systemic inconsistencies hidden behind algorithmic distractors.

The trap is set by providing a solvable binomial equation that yields exactly 8 integral pairs, tempting students to immediately conclude there are 8 solutions.

However, the linear equations for the fractional parts yield {x}=0.7\{x\} = 0.7 and {y}=0.9\{y\} = 0.9.

The critical Advanced-level disqualifier is the step function property [x+y]=[x]+[y]+[{x}+{y}][x+y] = [x] + [y] + [\{x\} + \{y\}].

Since 0.7+0.9≥10.7 + 0.9 \ge 1, this forces [x+y]=[x]+[y]+1[x+y] = [x] + [y] + 1, which directly violates the explicit constraint [x+y]=[x]+[y][x+y] = [x] + [y], rendering the entire feasible region a void zone.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Programming - Class 12
ConceptInconsistency Detection
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree