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Question #41768

Difficulty: 8/10 | 🟢 Free

The Question

Let F⃗(x)=∫(2xi^+2xj^)dx\vec{F}(x) = \int (2x \hat{i} + 2x \hat{j}) dx. The constant of integration is K⃗=Ci^−Cj^\vec{K} = C \hat{i} - C \hat{j}, where CC is an integer. Let V⃗1=F⃗(1)\vec{V}_1 = \vec{F}(1) and V⃗2=F⃗(2)\vec{V}_2 = \vec{F}(2). Consider the Linear Programming Problem: Maximize Z=x+yZ = x + y Subject to: r⃗⋅V⃗1≥12\vec{r} \cdot \vec{V}_1 \ge 12 r⃗⋅V⃗2≤18\vec{r} \cdot \vec{V}_2 \le 18 x≥0,y≥0x \ge 0, y \ge 0 where r⃗=xi^+yj^\vec{r} = x \hat{i} + y \hat{j}. Let SS be the set of all integers C∈[−10,10]C \in [-10, 10] for which the feasible region is non-empty. Find the number of elements in SS.

Options

  • A.

    12

  • B.

    21

  • C.

    10

  • D.

    14

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Unbounded Region Trap|Linear Independence vs Dependence|Integration Constant Trap

Why This Question Is Tricky

Common Mistakes

This question deploys the 'Integration Constant Trap' combined with an 'Unbounded/Infeasible Region Trap'.

Students typically solve the boundary equations, find the objective function value Z=x+y=2Z = x+y = 2, and incorrectly assume the feasible region is non-empty for all CC, leading to the trap answer 21.

However, the integration constant CC shifts the slopes and intercepts of the constraints.

By forcing the intersection point to be a function of CC, the feasible region completely collapses and becomes empty when CC crosses the critical thresholds (here, ∣C∣<5|C| < 5).

This tests the student's rigorous geometric understanding of LPP constraints beyond mere algebraic substitution.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Programming - Class 12
ConceptUnbounded Region Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree