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Question #41902

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∣111cos⁡(πx)11cos⁡(πx)∣x−1∣1∣f(x) = \begin{vmatrix} 1 & 1 & 1 \\ \cos(\pi x) & 1 & 1 \\ \cos(\pi x) & |x-1| & 1 \end{vmatrix}. Let SS be the number of points c∈(0,2)c \in (0, 2) such that f′(c)=0f'(c) = 0. Find the value of SS.

Options

  • A.

    0

  • B.

    1

  • C.

    2

  • D.

    3

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Differentiation of Determinants|Mean Value Theorem Applicability|Modulus Function Breakdown

Why This Question Is Tricky

Common Mistakes

This question tests the applicability of Rolle's Theorem on a determinant function containing a non-differentiable modulus term.

The trap is two-fold: First, students observe f(0)=f(2)=0f(0) = f(2) = 0 and reflexively apply Rolle's Theorem, assuming at least one root exists for f′(x)=0f'(x) = 0.

Second, if they differentiate the determinant row-wise, they encounter the derivative of ∣x−1∣|x-1|.

A common fatal mistake is assuming the derivative of ∣x−1∣|x-1| at x=1x=1 is 0 (or ignoring it because it's multiplied by a term that evaluates to 0), failing to realize the derivative becomes undefined, not zero.

By rigorously expanding and checking left/right derivatives, one finds f′(1)f'(1) is undefined and f′(x)f'(x) is strictly non-zero elsewhere, yielding 0 solutions.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterDeterminants - Class 12
ConceptDifferentiation of Determinants
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree