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Question #42006

Difficulty: 8/10 | 🟢 Free

The Question

A galvanometer of resistance GG and temperature coefficient of resistance α1\alpha_1 is converted into an ammeter of range II using a shunt of resistance SS and temperature coefficient α2\alpha_2. Assuming the full-scale deflection current IgI_g of the galvanometer is independent of temperature, which of the following expressions represents the fractional change in the range of the ammeter, ΔII\frac{\Delta I}{I}, for a small temperature rise ΔT\Delta T?

Options

  • A.

    GG+S(α1−α2)ΔT\frac{G}{G+S}(\alpha_1 - \alpha_2)\Delta T

  • B.

    SG+S(α1−α2)ΔT\frac{S}{G+S}(\alpha_1 - \alpha_2)\Delta T

  • C.

    (α1−α2)ΔT(\alpha_1 - \alpha_2)\Delta T

  • D.

    GG+S(α1+α2)ΔT\frac{G}{G+S}(\alpha_1 + \alpha_2)\Delta T

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Shunt Resistance Conversion|Temperature Coefficient (Alpha)|Relative Error Propagation in Powers

Why This Question Is Tricky

Common Mistakes

This question tests the propagation of relative error through a function where the variable of interest (range II) is not directly proportional to the ratio of the changing parameters (G/SG/S).

A common trap is assuming I∝G/SI \propto G/S, leading students to incorrectly state the fractional change as (α1−α2)ΔT(\alpha_1 - \alpha_2)\Delta T.

Furthermore, it forces students to recognize that the shunt resistance is not a static parameter and its temperature coefficient α2\alpha_2 must be accounted for using the quotient rule during differentiation, breaking the intuition of a 'fixed' ideal resistor.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterUnits and Measurements - Class 11 Part 1
ConceptRelative Error Propagation in Powers
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree