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Question #42030

Difficulty: 8/10 | 🟢 Free

The Question

Two parallel ideal conducting rails are placed at y=ay = a and y=−ay = -a in the xyxy-plane, extending from x=0x=0 to x→∞x \to \infty. They are connected at x=0x=0 by a zero-resistance wire. A non-uniform magnetic field B⃗=B0xak^\vec{B} = B_0 \frac{x}{a} \hat{k} exists in the region x>0x > 0. Two rigid conducting wires, W1W_1 and W2W_2, each with uniform resistance ρ\rho per unit length, are placed across the rails. W1W_1 is a straight wire connecting the points (x0,a)(x_0, a) and (x0,−a)(x_0, -a). W2W_2 is a semicircular wire bulging in the +x+x direction, with its ends at (x0,a)(x_0, a) and (x0,−a)(x_0, -a). Both wires are pulled independently in the +x+x direction with a constant velocity v⃗=v0i^\vec{v} = v_0 \hat{i}. At the instant x0=ax_0 = a, let P1P_1 and P2P_2 be the instantaneous thermal powers dissipated in W1W_1 and W2W_2 respectively. Neglecting self-inductance, what is the ratio P1P2\frac{P_1}{P_2}?

Options

  • A.

    8π(4+π)2\frac{8\pi}{(4+\pi)^2}

  • B.

    π2\frac{\pi}{2}

  • C.

    2π\frac{2}{\pi}

  • D.

    4π(2+π)2\frac{4\pi}{(2+\pi)^2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Displacement vs. Total Path Length|Motional EMF for Arbitrary Shapes|Velocity-Time Slope-Area Duality

Why This Question Is Tricky

Common Mistakes

This question tests the distinction between path-independent and path-dependent quantities in electromagnetic induction.

A common trap is assuming that motional EMF (∫(v⃗×B⃗)⋅dl⃗\int (\vec{v} \times \vec{B}) \cdot d\vec{l}) depends only on the displacement vector between the endpoints, which is ONLY true for uniform magnetic fields.

In a non-uniform field, the EMF depends on the actual geometry of the wire (or equivalently, the rate of change of flux depends on the area swept).

Students who incorrectly apply the uniform field shortcut will find equal EMFs for both wires and choose π/2\pi/2, failing to account for the spatial gradient of the magnetic field over the semicircular bulge.

Furthermore, Joule heating depends on the total path length (resistance), requiring careful synthesis of both arbitrary geometry integration and Ohmic losses.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptDisplacement vs. Total Path Length
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree