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Question #42043
The Question
A spherical radioactive particle of constant radius and initial mass falls vertically from rest in a viscous fluid. The mass of the particle decreases according to the decay law . Assume the decay process ejects the product particles such that they are left completely stationary in the lab frame immediately upon emission. The fluid exerts a drag force given by Stokes' Law, , where is the fluid viscosity and is the particle's velocity. Let . Which of the following differential equations correctly governs the velocity of the particle?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Kinematics of Vertical Free Fall|Statistical Nature of Decay|Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the correct application of Newton's Second Law for variable mass systems.
A common misconception among students is to blindly apply F = ma (yielding Option B) without accounting for the momentum carried away by the ejected mass.
By specifying that the decay products are left stationary in the lab frame, the relative velocity of the ejected mass is v_rel = -v.
This introduces a thrust term +v|dm/dt| into the equation of motion, making the governing equation equivalent to F_ext = d(mv)/dt.
The problem elegantly combines radioactive decay kinetics with fluid kinematics, requiring students to correctly couple the time-dependent mass m(t) = m_0 e^(-λt) and its derivative into the variable mass differential equation.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Motion in a Straight Line - Class 11 Part 1 |
| Concept | Kinematics of Vertical Free Fall |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |