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Question #42066
The Question
Two particles, and , are projected simultaneously in a uniform gravitational field . Particle is projected from the origin with initial velocity . Particle is projected from the point with initial velocity . Both particles experience an air drag force , where is the mass of the particle, is its velocity, and is a positive constant. If , what is the distance of closest approach between the two particles?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Relative Velocity in 2D|Collision Impulses|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the understanding of relative motion under velocity-dependent non-conservative forces.
The primary trap is assuming that the relative trajectory, which is a straight line, extends infinitely as it would in standard projectile motion.
Students often calculate the perpendicular distance from the origin to the line of relative motion (yielding ), failing to realize that the drag force exponentially decays the relative velocity.
This imposes a strict upper bound on the maximum relative displacement.
Consequently, the geometric closest point on the line is never reached, and the true distance of closest approach is the asymptotic limit of the trajectory.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Motion in a Plane - Class 11 Part 1 |
| Concept | Relative Velocity in 2D |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |