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Question #42083
The Question
A large closed tank contains a liquid of density . The liquid level is at a height above a small hole in the side of the tank. The gas above the liquid is maintained at a constant gauge pressure . A spherical droplet of radius and density emerges horizontally from the hole into the surrounding air. The droplet experiences a viscous drag force , where is the viscosity of air and is the droplet's velocity vector. Neglecting the buoyant force from the air, what is the horizontal displacement of the droplet at the exact instant its downward vertical velocity reaches ? (Assume acceleration due to gravity is ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Projectile on Inclined Plane|Torricelli’s Efflux Velocity|Viscosity and Stokes' Law
Why This Question Is Tricky
Common Mistakes
This question tests the transition from fluid dynamics (Torricelli's law with gauge pressure) to kinematics under non-conservative, velocity-dependent forces (Stokes' drag).
The primary trap lies in the assumption that the presence of a complex drag force () must explicitly manifest in the final kinematic relationship between and .
Students often get bogged down attempting to solve the coupled non-linear differential equations or incorrectly apply conservation of energy.
By isolating the time-dependent exponential decay factor in both orthogonal directions, the drag coefficient and mass elegantly cancel out, revealing a purely kinematic geometric constraint independent of the fluid's viscosity or the droplet's radius.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Motion in a Plane - Class 11 Part 1 |
| Concept | Projectile on Inclined Plane |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |