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Question #42166

Difficulty: 8/10 | 🟢 Free

The Question

One mole of a monatomic ideal gas of molar mass MM (in kg mol−1\text{kg mol}^{-1}) undergoes a cyclic process consisting of four steps: (I) Reversible isothermal expansion at a state where the variance of its 1D Maxwell-Boltzmann velocity distribution is σ12\sigma_1^2 (in m2s−2\text{m}^2\text{s}^{-2}). (II) Irreversible isochoric cooling by placing it in direct thermal contact with a heat reservoir until the velocity variance becomes σ22\sigma_2^2 (σ2<σ1\sigma_2 < \sigma_1). (III) Reversible isothermal compression at the new state. (IV) Irreversible isochoric heating by placing it in direct thermal contact with a heat reservoir until the velocity variance returns to σ12\sigma_1^2. What is the total entropy change of the universe (ΔSuniv\Delta S_{\text{univ}}) per mole of the gas for one complete cycle? (RR is the universal gas constant in J K−1mol−1\text{J K}^{-1}\text{mol}^{-1})

Options

  • A.

    32R(σ12−σ22)2σ12σ22\frac{3}{2}R \frac{(\sigma_1^2 - \sigma_2^2)^2}{\sigma_1^2 \sigma_2^2}

  • B.

    0

  • C.

    32Rln⁡(σ12σ22)\frac{3}{2}R \ln\left(\frac{\sigma_1^2}{\sigma_2^2}\right)

  • D.

    12R(σ12−σ22)2σ12σ22\frac{1}{2}R \frac{(\sigma_1^2 - \sigma_2^2)^2}{\sigma_1^2 \sigma_2^2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

State Function vs Path Function|Entropy and Reversibility|Maxwell-Boltzmann Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental distinction between the entropy change of a system and the universe in cyclic processes, specifically targeting the misconception that ΔSuniverse=0\Delta S_{\text{universe}} = 0 for any cycle.

Students often memorize that entropy is a state function and incorrectly apply ∮dS=0\oint dS = 0 to the universe rather than just the system.

By embedding the temperature states within the variance of the Maxwell-Boltzmann velocity distribution (σ2=RT/M\sigma^2 = RT/M), the problem forces students to translate microscopic statistical parameters into macroscopic thermodynamic variables.

Furthermore, it traps students who fail to recognize that irreversible heat transfer across a finite temperature difference generates entropy, requiring them to calculate the exact entropy production (ΔSsurr\Delta S_{\text{surr}}) at the thermal reservoirs.

Option D serves as an additional trap for students who confuse the 1D velocity distribution variance with the degrees of freedom, incorrectly using Cv=R/2C_v = R/2 instead of 3R/23R/2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermodynamics - Class 11 Part 2
ConceptState Function vs Path Function
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree