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Question #42204

Difficulty: 8/10 | 🟢 Free

The Question

Two long, thin cylindrical rods, Rod 1 and Rod 2, are joined end-to-end at x=0x=0. Both rods have the same uniform cross-sectional area and the same uniform density ρ\rho. The materials of both rods have an identical shear modulus GG. Rod 1 has a bulk modulus B1=23GB_1 = \frac{2}{3}G. Rod 2 is made of an ideal incompressible material (B2→∞B_2 \to \infty). A longitudinal displacement wave si(x,t)=Aisin⁡(ωt−k1x)s_i(x,t) = A_i \sin(\omega t - k_1 x) travels through Rod 1 towards the junction. If the reflected wave is sr(x,t)=Arsin⁡(ωt+k1x)s_r(x,t) = A_r \sin(\omega t + k_1 x), what is the amplitude reflection coefficient R=ArAiR = \frac{A_r}{A_i}?

Options

  • A.

    26−52\sqrt{6} - 5

  • B.

    -1

  • C.

    5−265 - 2\sqrt{6}

  • D.

    −15-\frac{1}{5}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Poisson's Ratio Limits|Boundary Condition Reflection|Waves

Why This Question Is Tricky

Common Mistakes

This question tests the understanding of longitudinal wave propagation in bounded media (thin rods) versus bulk media.

A common misconception is that an incompressible material (B→∞B \to \infty) implies an infinite wave speed, leading students to incorrectly conclude that the acoustic impedance Z2→∞Z_2 \to \infty and the reflection coefficient R=−1R = -1 (total reflection).

However, in a thin rod, lateral expansion (Poisson effect) allows longitudinal waves to propagate at a finite speed governed by Young's modulus YY.

Even as B→∞B \to \infty, YY approaches a finite limit (3G3G), resulting in a finite impedance and partial reflection.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Solids - Class 11 Part 2
ConceptPoisson's Ratio Limits
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree