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Question #42267

Difficulty: 8/10 | 🟢 Free

The Question

A thin non-conducting rod of length 2L2L lies along the xx-axis, centered at the origin. It carries a non-uniform linear charge density λ(x)=λ0∣x∣L\lambda(x) = \lambda_0 \frac{|x|}{L}, where λ0\lambda_0 is a positive constant. An external agent moves a point charge qq from point A(0,L,0)A(0, L, 0) to point B(0,0,34L)B\left(0, 0, \frac{3}{4}L\right) along a complex curved path Γ\Gamma parameterized by r⃗(t)=Lsin⁡(πt)i^+Lcos⁡2(πt2)j^+34Lsin⁡2(πt2)k^\vec{r}(t) = L\sin(\pi t)\hat{i} + L\cos^2\left(\frac{\pi t}{2}\right)\hat{j} + \frac{3}{4}L\sin^2\left(\frac{\pi t}{2}\right)\hat{k} for t∈[0,1]t \in [0,1]. What is the work done by the electric field on the charge qq during this motion?

Options

  • A.

    qλ04πϵ0(22−3)\frac{q \lambda_0}{4\pi\epsilon_0} (2\sqrt{2} - 3)

  • B.

    qλ04πϵ0(3−22)\frac{q \lambda_0}{4\pi\epsilon_0} (3 - 2\sqrt{2})

  • C.

    qλ02πϵ0(2−1)\frac{q \lambda_0}{2\pi\epsilon_0} (\sqrt{2} - 1)

  • D.

    qλ04πϵ0(22−1)\frac{q \lambda_0}{4\pi\epsilon_0} (2\sqrt{2} - 1)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Potential vs Field Relationship|Conservative Field Path Independence|Continuous Charge Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to recognize path independence in a conservative vector field, specifically avoiding the brute-force calculation of a complex line integral.

By providing a non-uniform charge distribution and an intimidating 3D parametric path that leaves the symmetry plane, students are baited into attempting to find the electric field vector at arbitrary points in space—a mathematically prohibitive task.

The correct approach requires identifying that the electrostatic force is conservative, meaning work depends only on the scalar potential difference between the initial and final points, both of which conveniently lie on the yz-plane where the potential integral is easily solvable.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptPotential vs Field Relationship
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree