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Question #42268

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge qq is located at the origin of a coordinate system. At time t=0t=0, it is projected with an initial velocity v⃗=v0i^\vec{v} = v_0 \hat{i}. A time-dependent, spatially uniform electric field E⃗=cti^\vec{E} = c t \hat{i} is present in the region, where cc is a positive constant. What is the work done by the electric field on the particle during the time interval from t=0t=0 to t=Tt=T?

Options

  • A.

    qcv0T22+q2c2T48m\frac{q c v_0 T^2}{2} + \frac{q^2 c^2 T^4}{8m}

  • B.

    qcv0T22\frac{q c v_0 T^2}{2}

  • C.

    qcv0T2+q2c2T44mq c v_0 T^2 + \frac{q^2 c^2 T^4}{4m}

  • D.

    qcv0T22+q2c2T42m\frac{q c v_0 T^2}{2} + \frac{q^2 c^2 T^4}{2m}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Potential vs Field Relationship|Work-Energy Theorem Validity|Motion in a Straight Line

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle time-dependent fields where the concept of a static scalar electric potential is ill-defined.

A common trap is attempting to calculate work using W=∫qE⃗⋅dx⃗W = \int q \vec{E} \cdot d\vec{x} while incorrectly assuming the particle's trajectory is unperturbed (dx=v0dtdx = v_0 dt), leading to the partial answer.

By forcing the field to be time-varying (∂E⃗/∂t≠0\partial \vec{E}/\partial t \neq 0), students must abandon static potential gradients and directly apply the Work-Energy theorem, accounting for the field's continuous effect on the particle's velocity.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptPotential vs Field Relationship
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree