Start Learning Free

Before You Begin

Question #42281

Difficulty: 8/10 | 🟢 Free

The Question

A solid sphere of radius RR and total mass MM has a radially varying mass density ρ(r)=ρ0(1−rR)\rho(r) = \rho_0 \left(1 - \frac{r}{R}\right), where rr is the distance from the center. A narrow, smooth radial tunnel is drilled into the sphere. A small particle of mass mm is projected from a depth r=R2r = \frac{R}{2} inside the tunnel towards the surface. What is the minimum projection speed v0v_0 required for the particle to escape the gravitational pull of the sphere?

Options

  • A.

    1213GMR\frac{1}{2}\sqrt{\frac{13GM}{R}}

  • B.

    11GM4R\sqrt{\frac{11GM}{4R}}

  • C.

    3GMR\sqrt{\frac{3GM}{R}}

  • D.

    1215GMR\frac{1}{2}\sqrt{\frac{15GM}{R}}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Gravitational Potential Energy (System)|Mechanical Energy Conservation|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental definition of gravitational potential inside a non-uniform mass distribution.

A common trap for students is to incorrectly assume that the potential inside the sphere can be calculated by treating only the enclosed mass m(r)m(r) as a point mass at the center, yielding V=−Gm(r)/rV = -Gm(r)/r.

This completely ignores the gravitational potential contribution from the outer spherical shells (−∫Gdm/r′- \int G dm/r').

The problem forces the explicit derivation of the potential function V(r)V(r) via integration of both inner and outer mass elements before applying mechanical energy conservation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptGravitational Potential Energy (System)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree