Start Learning Free

Before You Begin

Question #42296

Difficulty: 8/10 | 🟢 Free

The Question

A cylindrical metallic wire of length L0L_0, radius rr, and emissivity ϵ\epsilon hangs vertically from a rigid support, carrying a mass MM at its lower end. At ambient temperature T0T_0, the free electron density is nn and the relaxation time is τ0\tau_0. When a constant current II flows through the wire, its temperature increases by ΔT\Delta T. The relaxation time decreases as τ=τ0/(1+βΔT)\tau = \tau_0 / (1 + \beta \Delta T), and the Young's modulus decreases as Y=Y0−αΔTY = Y_0 - \alpha \Delta T. The wire loses heat only via radiation to the surroundings at T0T_0 (Stefan-Boltzmann constant σs\sigma_s). Assuming ΔT≪T0\Delta T \ll T_0 and ignoring linear thermal expansion, what is the steady-state increase in the length of the wire due to the current? (Let mem_e and ee be the mass and charge of an electron).

Options

  • A.

    MgL0αI2meπr2Y02(8π2r3ne2τ0ϵσsT03−I2βme)\frac{M g L_0 \alpha I^2 m_e}{\pi r^2 Y_0^2 \left( 8 \pi^2 r^3 n e^2 \tau_0 \epsilon \sigma_s T_0^3 - I^2 \beta m_e \right)}

  • B.

    MgL0αI2me8π3r5Y02ne2τ0ϵσsT03\frac{M g L_0 \alpha I^2 m_e}{8 \pi^3 r^5 Y_0^2 n e^2 \tau_0 \epsilon \sigma_s T_0^3}

  • C.

    MgL0αI2meπr2Y0(8π2r3ne2τ0ϵσsT03−I2βme)\frac{M g L_0 \alpha I^2 m_e}{\pi r^2 Y_0 \left( 8 \pi^2 r^3 n e^2 \tau_0 \epsilon \sigma_s T_0^3 - I^2 \beta m_e \right)}

  • D.

    MgL0αI2meπr2Y02(2π2r3ne2τ0ϵσsT03−I2βme)\frac{M g L_0 \alpha I^2 m_e}{\pi r^2 Y_0^2 \left( 2 \pi^2 r^3 n e^2 \tau_0 \epsilon \sigma_s T_0^3 - I^2 \beta m_e \right)}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Young's Modulus Sensitivity|Relaxation Time Dependency|Binomial Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the coupled understanding of Drude's model, thermal radiation, and elasticity.

The primary trap lies in assuming the electrical heating power is independent of temperature (P=I2R0P = I^2 R_0), ignoring the temperature dependence of the relaxation time which creates a feedback loop in the steady-state temperature.

Additionally, students often fail to correctly linearize the Stefan-Boltzmann law using the binomial approximation ((T0+ΔT)4−T04≈4T03ΔT(T_0+\Delta T)^4 - T_0^4 \approx 4T_0^3\Delta T) or incorrectly apply the Taylor expansion for the change in elongation (ΔL∝1/Y\Delta L \propto 1/Y), leading to missing the squared term Y02Y_0^2 in the denominator.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Solids - Class 11 Part 2
ConceptYoung's Modulus Sensitivity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree