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Question #42298

Difficulty: 8/10 | 🟢 Free

The Question

A mechanical spring undergoing cyclic deformation exhibits elastic hysteresis, dissipating energy ΔE=αx02\Delta E = \alpha x_0^2 per cycle, where x0x_0 is the displacement amplitude. In a direct electromechanical analogy, this spring is modeled as an inductor with a lossy material core in a series RLCRLC circuit. The displacement xx maps to the charge qq on the capacitor, and the velocity vv maps to the current ii. The hysteresis loss is represented by an equivalent series resistance RR. If αe\alpha_e is the electrical analog of the constant α\alpha, what is the value of RR in terms of αe\alpha_e, the inductance LL, and the capacitance CC? Assume the damping is small.

Options

  • A.

    αeπLC\frac{\alpha_e}{\pi} \sqrt{LC}

  • B.

    αe2πLC\frac{\alpha_e}{2\pi} \sqrt{LC}

  • C.

    2αeπLC\frac{2\alpha_e}{\pi} \sqrt{LC}

  • D.

    αe4πLC\frac{\alpha_e}{4\pi} \sqrt{LC}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Elastic Hysteresis Loop|LC Circuit Oscillations|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to map mechanical hysteresis (energy loss per cycle) to electrical resistive dissipation in an RLC circuit.

The core trap lies in distinguishing between power (energy per unit time) and energy dissipated per cycle.

Students often incorrectly equate the hysteresis constant directly to resistance without integrating over the cycle, missing the πω\pi \omega factor.

Furthermore, it requires correctly relating the amplitude of charge q0q_0 to the amplitude of current i0=q0ωi_0 = q_0 \omega, reinforcing the phase and amplitude relationships in oscillatory systems.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMechanical Properties of Solids - Class 11 Part 2
ConceptElastic Hysteresis Loop
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree