Start Learning Free

Before You Begin

Question #42328

Difficulty: 8/10 | 🟢 Free

The Question

A horizontal, perfectly insulated cylinder is placed in a vacuum and contains 1 mol1 \text{ mol} of a diatomic gas at an initial temperature T0T_0. A frictionless, adiabatic piston of mass MM is given an initial inward velocity v0v_0 such that Mv02=18RT0M v_0^2 = 18 R T_0, compressing the gas. Assuming the gas maintains internal thermal equilibrium, and due to the excitation of vibrational degrees of freedom at higher energies, its molar heat capacity at constant volume varies as CV(T)=52R+2R(T−T0T0)C_V(T) = \frac{5}{2}R + 2R\left(\frac{T - T_0}{T_0}\right) for T≥T0T \ge T_0. What is the maximum temperature TmaxT_{max} reached by the gas?

Options

  • A.

    235T0\frac{23}{5} T_0

  • B.

    3 T_0

  • C.

    257T0\frac{25}{7} T_0

  • D.

    2 T_0

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Mechanical Energy Conservation|Molecular Degrees of Freedom|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the application of the First Law of Thermodynamics and mechanical energy conservation in a coupled macroscopic-microscopic system.

The lethal trap lies in the assumption of a constant specific heat capacity (CV=52RC_V = \frac{5}{2}R or 72R\frac{7}{2}R).

Students often blindly use ΔU=nCVΔT\Delta U = n C_V \Delta T, failing to recognize that at high energies, the activation of vibrational degrees of freedom makes the internal energy a non-linear function of temperature.

By forcing the integration of dU=CV(T)dTdU = C_V(T) dT, the problem evaluates the student's fundamental understanding of internal energy beyond standard rigid diatomic models.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWork, Energy, and Power - Class 11 Part 1
ConceptMechanical Energy Conservation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree