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Question #42347
The Question
A block of mass is placed on a rough wedge of angle . The coefficient of kinetic friction between the block and the wedge is . The wedge is forced to accelerate horizontally to the left, and its acceleration varies with time as . At , the block is released from rest relative to the wedge. Assuming the wedge is long enough so the block does not fall off, find the work done by the kinetic friction force on the block in the laboratory frame during the time interval to . (Take )
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Work Done by Friction|Pseudo Force Directionality|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the rigorous application of the Work-Energy theorem in a non-inertial setup, specifically targeting the frame-dependency of work.
A common JEE pitfall is equating the work done by friction in the non-inertial frame (which only accounts for internal energy dissipation, ) to the total work done by friction in the laboratory frame.
Students must correctly map the non-constant friction force back to the lab frame by explicitly integrating using the vector relation .
The parameters are carefully chosen so that the terms in the power polynomial cancel out, rewarding students who set up the full integral correctly.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Work, Energy, and Power - Class 11 Part 1 |
| Concept | Work Done by Friction |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |