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Question #42356

Difficulty: 8/10 | 🟢 Free

The Question

A rigid cylindrical tube of mass MM and length LL is initially at rest in deep space, free from any external forces. Inside the tube, a non-uniform liquid of mass MM initially occupies the left half of the tube (0≤x≤L/20 \le x \le L/2, where xx is the distance from the left end of the tube). The linear mass density of the liquid is given by λ(x)=λ0sin⁡(πxL)\lambda(x) = \lambda_0 \sin\left(\frac{\pi x}{L}\right). An internal pump transfers the entire liquid to the right half of the tube (L/2≤x≤LL/2 \le x \le L), where it settles with the density profile λ(x)=λ0sin⁡(πxL)\lambda(x) = \lambda_0 \sin\left(\frac{\pi x}{L}\right). What is the magnitude of the absolute displacement of the tube?

Options

  • A.

    L(π−22π)L \left( \frac{\pi - 2}{2\pi} \right)

  • B.

    L4\frac{L}{4}

  • C.

    L2\frac{L}{2}

  • D.

    L(π−2π)L \left( \frac{\pi - 2}{\pi} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

System vs Particle Displacement|Collision Impulses|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the principle of conservation of momentum and center of mass displacement in a variable-density system.

A common trap is assuming the liquid has uniform density, which incorrectly places the initial and final liquid CMs at L/4L/4 and 3L/43L/4, leading to a displacement of L/4L/4.

Another trap is neglecting the mass of the tube itself, which results in calculating the displacement required to keep only the liquid's CM stationary.

Students must correctly set up the integral for the center of mass of a continuous sinusoidal mass distribution and apply the stationary CM condition for the combined two-body system.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSystem of Particles and Rotational Motion - Class 11 Part 1
ConceptSystem vs Particle Displacement
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree