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Question #42374
The Question
A uniform rod of mass and length is pivoted at a frictionless hinge located at a distance from its center of mass. The rod is released from rest at an initial angular displacement from the vertical downward position. Since is large, the small-angle approximation () is invalid. Let be the acceleration due to gravity. Which of the following expressions represents the exact time period of the resulting oscillations?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Moment of Inertia (MOI) Symmetry|Compound Pendulum Period|SHM Definition via Differential Equation
Why This Question Is Tricky
Common Mistakes
This question tests the transition from standard Simple Harmonic Motion to non-linear large-angle dynamics.
Students often incorrectly apply the small-angle formula or fail to re-evaluate the moment of inertia about the new pivot using the Parallel Axis Theorem (leading to Option D).
Furthermore, it requires setting up the exact differential equation via Energy Conservation rather than the torque equation, recognizing that the restoring torque cannot be linearized, which naturally leads to an elliptic integral for the exact time period.
Option B traps students who forget to multiply the quarter-period integral by 4.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | System of Particles and Rotational Motion - Class 11 Part 1 |
| Concept | Moment of Inertia (MOI) Symmetry |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |