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Question #42397
The Question
A gyroscope consists of a thin uniform ring of initial mass and radius , mounted on a massless shaft of length . The shaft is pivoted at a fixed origin . The ring spins about the shaft with an initial angular velocity . A constant downward force is applied at the center of the ring (ignore gravity). The ring loses mass at a constant rate such that its mass at time is . The detached mass is ejected radially outwards relative to the ring's center. Assuming the rapid spin approximation (), find the total angle of precession of the shaft from to .
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Gyroscopic Stability|Variable Mass Systems|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
This question tests the application of the angular momentum theorem to a variable mass system undergoing gyroscopic precession.
A common trap is assuming that because there is no external torque along the spin axis, the spin angular momentum is conserved, leading to a constant precession rate (Option B).
However, students must recognize that the radially ejected mass carries away angular momentum.
Applying the generalized Newton's Second Law for rotation reveals that the spin angular velocity remains constant, causing to decrease proportionally with mass.
Consequently, the precession frequency increases over time, requiring integration to find the true total precession angle.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | System of Particles and Rotational Motion - Class 11 Part 1 |
| Concept | Gyroscopic Stability |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |