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Question #42439

Difficulty: 8/10 | 🟢 Free

The Question

A uniform solid cylinder of mass MM and radius RR rolls without slipping on a rough horizontal plane with a coefficient of static friction μ\mu. A torsional spring of stiffness κ\kappa is attached to its central axis, providing a restoring torque τ=−κθ\tau = -\kappa \theta proportional to the angle of rotation θ\theta, without exerting any net horizontal force. Determine the maximum angular amplitude θmax\theta_{\text{max}} of the oscillation such that the cylinder never slips.

Options

  • A.

    3μMgR2κ\frac{3 \mu M g R}{2 \kappa}

  • B.

    μMgRκ\frac{\mu M g R}{\kappa}

  • C.

    2μMgRκ\frac{2 \mu M g R}{\kappa}

  • D.

    3μMgRκ\frac{3 \mu M g R}{\kappa}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Static Friction Threshold|Torsional Oscillations|Physical Pendulum Inertia

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple rotational and translational dynamics under the constraint of static friction.

A common trap is assuming that the system is in quasi-static equilibrium or ignoring the inertial torque, leading to the incorrect torque balance κθ=fR\kappa \theta = f R and the erroneous answer θmax=μMgR/κ\theta_{\text{max}} = \mu M g R / \kappa.

Students must realize that the torsional spring drives both angular and linear acceleration.

By correctly applying Newton's second law for translation (f=Maf = M a) and rotation (−κθ−fR=Iα-\kappa \theta - f R = I \alpha) along with the rolling constraint (a=Rαa = R \alpha), the true inertial resistance of the disk is accounted for, revealing that friction only provides a fraction of the total restoring torque.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterLaws of Motion - Class 11 Part 1
ConceptStatic Friction Threshold
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree