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Question #42510

Difficulty: 8/10 | 🟢 Free

The Question

A macromolecule of mass mm with ff internal degrees of freedom is attached to a spring of force constant kk and undergoes weakly damped oscillations along the xx-axis. It experiences a drag force Fd=−bvF_d = -b v, where the damping coefficient bb is directly proportional to the molecule's instantaneous internal energy UU, such that b=βUb = \beta U (β\beta is a positive constant). Initially (t=0t=0), the molecule is in thermal equilibrium with the surrounding fluid at temperature T0T_0, and is given an initial macroscopic oscillation energy E0E_0. Assuming the energy dissipated by the drag force is entirely absorbed by the molecule's internal degrees of freedom (with negligible heat transfer to the fluid), which of the following expressions gives the time t1/2t_{1/2} required for the oscillation energy to decrease to E0/2E_0/2? (Assume kBk_B is the Boltzmann constant).

Options

  • A.

    mβ(E0+f2kBT0)ln⁡(2+2E0fkBT0)\frac{m}{\beta \left(E_0 + \frac{f}{2} k_B T_0\right)} \ln \left( 2 + \frac{2 E_0}{f k_B T_0} \right)

  • B.

    2mln⁡2βfkBT0\frac{2 m \ln 2}{\beta f k_B T_0}

  • C.

    mβE0ln⁡2\frac{m}{\beta E_0} \ln 2

  • D.

    mβ(E0+fkBT0)ln⁡(1+E0fkBT0)\frac{m}{\beta \left(E_0 + f k_B T_0\right)} \ln \left( 1 + \frac{E_0}{f k_B T_0} \right)

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Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Molecular Degrees of Freedom|Damped Oscillation Equation|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of macroscopic mechanical dissipation with microscopic statistical thermodynamics.

The primary trap is treating the damping coefficient as a constant external parameter (Option B), which ignores the fact that internal heat dissipation (vibrational/rotational relaxation) shifts the effective drag force.

Students must recognize that the dissipated macroscopic energy acts as a heat source for the internal degrees of freedom, requiring a coupled differential equation (a logistic decay model) rather than standard exponential decay.

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Question Information

SubjectPhysics
ChapterKinetic Theory - Class 11 Part 2
ConceptMolecular Degrees of Freedom
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree