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Question #42579

Difficulty: 8/10 | 🟢 Free

The Question

A vertical cylindrical tank of height HH contains an ideal gas of molar mass MM in hydrostatic equilibrium under a uniform gravitational field gg. The temperature of the gas decreases linearly with height. The RMS speed of the gas molecules at the bottom (y=0y=0) is v0v_0, and at the top (y=Hy=H) is vHv_H. The pressure at the top of the tank is PHP_H. A small orifice is opened at the bottom of the tank, allowing the gas to escape into an external environment maintained at pressure PHP_H. Assuming the efflux velocity is given by ve=2ΔPρ0v_e = \sqrt{\frac{2 \Delta P}{\rho_0}}, where ΔP\Delta P is the pressure difference across the orifice and ρ0\rho_0 is the density of the gas at the bottom, which of the following expressions correctly represents vev_e?

Options

  • A.

    v023[1−(vHv0)6gHv02−vH2]v_0 \sqrt{\frac{2}{3} \left[ 1 - \left( \frac{v_H}{v_0} \right)^{\frac{6 g H}{v_0^2 - v_H^2}} \right]}

  • B.

    2gH\sqrt{2 g H}

  • C.

    v023[1−exp⁡(−3gHv02)]v_0 \sqrt{\frac{2}{3} \left[ 1 - \exp\left(-\frac{3 g H}{v_0^2}\right) \right]}

  • D.

    v01−(vHv0)4gHv02−vH2v_0 \sqrt{1 - \left( \frac{v_H}{v_0} \right)^{\frac{4 g H}{v_0^2 - v_H^2}}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

RMS vs Average vs Most Probable Speed|Torricelli’s Efflux Velocity|Hydrostatic Paradox

Why This Question Is Tricky

Common Mistakes

Students often incorrectly apply Torricelli's law (v=2gHv = \sqrt{2gH}) to gases, ignoring compressibility and the variable density of the atmospheric column.

Furthermore, when attempting to find the pressure difference, they may falsely assume an isothermal profile (P=P0e−ρgh/PP = P_0 e^{-\rho g h/P}) or fail to link the macroscopic temperature gradient to the microscopic RMS speeds (T∝vrms2T \propto v_{rms}^2).

The trap lies in assuming pressure depends only on head height (P=hρgP = h\rho g) rather than the integral of the distribution function over a linearly varying temperature profile, leading to incorrect pressure ratios.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterKinetic Theory - Class 11 Part 2
ConceptRMS vs Average vs Most Probable Speed
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree