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Question #42584
The Question
A perfectly absorbing wall of work function () separates a vacuum from an ideal monoatomic gas (mass , number density , temperature ). Gas molecules striking the wall with normal kinetic energy are absorbed, transferring their momentum to the wall.
Simultaneously, the vacuum side of the wall is illuminated by a photon beam of intensity , which is completely absorbed. The radiation pressure from the photons exactly balances the partial pressure exerted only by the absorbed gas molecules.
Assuming the gas follows the Maxwell-Boltzmann velocity distribution , which of the following represents the intensity ?
(Hint: For large , use the approximation )
Options
- A.
- B.
- C.
- D.
c n \phi e^{-\phi / k T}
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Pressure-Kinetic Energy Relation|Einstein's Photoelectric Equation|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the fundamental definition of kinetic pressure as a momentum flux integral over a velocity distribution, rather than a simple macroscopic average.
The primary trap (Option B) is the assumption that the partial pressure of high-energy molecules can be found by multiplying the average gas pressure () by the fraction of molecules exceeding the threshold energy .
This incorrect approach ignores that higher-velocity molecules transfer proportionally more momentum per collision and collide more frequently, leading to a missing factor of .
Additionally, it couples the stochastic nature of gas collisions with macroscopic radiation pressure, forcing students to rigorously apply the Maxwell-Boltzmann distribution to a boundary condition.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Kinetic Theory - Class 11 Part 2 |
| Concept | Pressure-Kinetic Energy Relation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |