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Question #42641

Difficulty: 8/10 | 🟢 Free

The Question

A long string under constant tension TT has a variable mass per unit length μ(x)=μ0(1+αx)4\mu(x) = \mu_0 (1 + \alpha x)^4 for x≥0x \ge 0. A single positive transverse wave pulse (displacement y≥0y \ge 0) is generated at x=0x=0 with an initial amplitude A0A_0 and propagates in the +x+x direction. The string rests on a surface that exerts a constant transverse kinetic friction force of magnitude fkf_k per unit length, which always opposes the transverse velocity of the string particles. Assuming fkf_k is sufficiently small such that the spatial variation of the pulse amplitude is predominantly governed by the non-uniform density (WKB approximation), what is the magnitude of the total work done by friction on the string segment from x=0x=0 to x=Lx=L during the complete passage of the pulse?

Options

  • A.

    2fkA0αln⁡(1+αL)\frac{2 f_k A_0}{\alpha} \ln(1 + \alpha L)

  • B.

    fkA0αln⁡(1+αL)\frac{f_k A_0}{\alpha} \ln(1 + \alpha L)

  • C.

    2fkA0α(1−11+αL)\frac{2 f_k A_0}{\alpha} \left( 1 - \frac{1}{1+\alpha L} \right)

  • D.

    2fkA0L2 f_k A_0 L

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Particle Velocity vs. Wave Velocity|Work-Energy Theorem Validity|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of the Work-Energy theorem with wave propagation in non-uniform media.

A common trap is assuming the wave amplitude remains constant (A=A0A=A_0), leading to the incorrect work calculation 2fkA0L2 f_k A_0 L.

Another frequent mistake is incorrectly applying energy conservation by assuming energy density E∝μA2E \propto \mu A^2 is constant, which yields an incorrect amplitude scaling of A∝μ−1/2A \propto \mu^{-1/2}.

Students must recognize that the local impedance Tμ(x)\sqrt{T\mu(x)} dictates the power flux, leading to the WKB scaling A(x)∝μ(x)−1/4A(x) \propto \mu(x)^{-1/4}.

Furthermore, they must correctly map the macroscopic wave amplitude to the microscopic transverse distance (2A2A) traveled by the particles to compute the work done by the non-conservative friction force.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptParticle Velocity vs. Wave Velocity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree