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Question #42692

Difficulty: 8/10 | 🟢 Free

The Question

A capacitor of capacitance CC is initially charged to a potential difference V0V_0. It is connected in a series circuit containing an open switch SS, an uncharged capacitor of capacitance 2C2C, and an ideal solenoid of self-inductance LL. The ohmic resistance of the circuit is negligible. If the switch SS is closed at t=0t = 0, what is the maximum potential difference developed across the initially uncharged capacitor during the subsequent LC oscillations?

Options

  • A.

    V03\frac{V_0}{3}

  • B.

    2V03\frac{2V_0}{3}

  • C.

    V02\frac{V_0}{2}

  • D.

    V_0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Common Potential Redistribution|Self-Inductance of Solenoid|Average Power over Cycle|Differential Equations

Why This Question Is Tricky

Common Mistakes

This question tests the 'instantaneous charge equalization' fallacy.

Students often incorrectly apply electrostatic charge redistribution, assuming the capacitors simply reach a common potential V=CV0C+2C=V03V = \frac{C V_0}{C + 2C} = \frac{V_0}{3}.

They fail to recognize that the solenoid's self-inductance creates a back-EMF (LdidtL \frac{di}{dt}) that governs the transient dynamics.

Instead of settling instantly, the system forms an LC oscillator.

The magnetic inertia of the inductor causes the charge transfer to overshoot the electrostatic equilibrium point, reaching exactly twice the equilibrium charge before the current reverses, resulting in a maximum potential difference of 2V03\frac{2V_0}{3}.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptCommon Potential Redistribution
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree