Start Learning Free

Before You Begin

Question #42704

Difficulty: 8/10 | 🟢 Free

The Question

A particle of rest mass m0m_0 and charge −q-q is projected tangentially with speed v0v_0 from a radial distance r=2Rr = 2R in the vacuum space between two fixed concentric non-conducting spherical shells of radii RR and 4R4R. The inner shell carries a uniformly distributed charge +Q+Q, while the outer shell carries a uniformly distributed charge −Q-Q. The particle's trajectory just grazes the inner shell. It is given that the characteristic electrostatic energy parameter U0=qQ4πϵ0RU_0 = \frac{qQ}{4 \pi \epsilon_0 R} is equal to 10−6m0c210^{-6} m_0 c^2, where cc is the speed of light in vacuum. Which of the following is the correct expression for the required projection speed v0v_0?

Options

  • A.

    10−33c\frac{10^{-3}}{\sqrt{3}} c

  • B.

    2310−3c\sqrt{\frac{2}{3}} 10^{-3} c

  • C.

    10−3c10^{-3} c

  • D.

    10−32c\frac{10^{-3}}{2} c

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Potential of Concentric Shells|Quantization of Angular Momentum|Trajectory of Charged Particle

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of electrostatic potential with angular momentum conservation, while deploying a 'masterstroke' trap regarding relativistic mass variation.

By explicitly defining the energy parameter U0U_0 in terms of the rest mass energy m0c2m_0 c^2 and the speed of light cc, students are baited into assuming they must use relativistic momentum (L=γm0vrL = \gamma m_0 v r) and total energy (E=γm0c2+UE = \gamma m_0 c^2 + U).

However, evaluating the energy scale (U0=10−6m0c2U_0 = 10^{-6} m_0 c^2) reveals the motion is highly non-relativistic (v∼10−3cv \sim 10^{-3} c).

Students who fall for the trap will suffer severe algebraic bloat attempting to solve transcendental equations, whereas recognizing the classical limit allows a swift solution using standard conservation laws.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptPotential of Concentric Shells
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree