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Question #42714

Difficulty: 8/10 | 🟢 Free

The Question

A parallel plate capacitor with circular plates of radius RR is being charged by a long cylindrical copper wire of radius rr (where r<Rr < R). The free electron density in the copper wire is nn, and the magnitude of the elementary charge is ee. At a given instant, the electrons in the wire are moving with a drift velocity of magnitude vdv_d. Assuming the electric field EE between the capacitor plates is uniform and neglecting fringe effects, what is the rate of change of the electric field ∂E∂t\frac{\partial E}{\partial t} in the region between the plates at this instant? Let ϵ0\epsilon_0 be the permittivity of free space.

Options

  • A.

    ner2vdϵ0R2\frac{n e r^2 v_d}{\epsilon_0 R^2}

  • B.

    nevdϵ0\frac{n e v_d}{\epsilon_0}

  • C.

    neR2vdϵ0r2\frac{n e R^2 v_d}{\epsilon_0 r^2}

  • D.

    nervdϵ0R\frac{n e r v_d}{\epsilon_0 R}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Drift Velocity Mechanism|Displacement Current Source|Continuous Charge Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to bridge microscopic conduction kinetics with macroscopic Maxwellian electrodynamics.

The primary trap lies in the misapplication of the continuity equation by incorrectly equating the conduction current density (JcJ_c) in the wire directly to the displacement current density (JdJ_d) between the plates, which leads to the erroneous answer nevdϵ0\frac{n e v_d}{\epsilon_0}.

Students often forget that while total current (II) is continuous across the capacitor boundary due to the conservation of charge, the current density (JJ) is not, because the cross-sectional area of the wire (rr) differs from the area of the capacitor plates (RR).

The correct approach requires equating the total conduction current to the total displacement current, thereby incorporating the geometric area ratio (r/R)2(r/R)^2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptDrift Velocity Mechanism
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree