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Question #42726

Difficulty: 8/10 | 🟢 Free

The Question

A thin insulating disk of uniform mass density, total mass MM, and radius RR lies in the xyxy-plane. It is rotating with a constant angular velocity ω⃗=ωk^\vec{\omega} = \omega \hat{k} about its central axis (the zz-axis). The disk has a non-uniform surface charge density given by σ(r)=σ0rR\sigma(r) = \sigma_0 \frac{r}{R}, where rr is the radial distance from the center and σ0\sigma_0 is a positive constant. A uniform magnetic field B⃗=B0i^\vec{B} = B_0 \hat{i} is applied across the region. Assume the setup is in a gravity-free space and the disk is pivoted at its center. The magnetic torque causes the rotation axis of the disk to undergo gyroscopic precession. Assuming the precession angular velocity Ωp\Omega_p is much smaller than ω\omega, what is the magnitude of the precession angular velocity Ωp\Omega_p?

Options

  • A.

    2πσ0B0R25M\frac{2 \pi \sigma_0 B_0 R^2}{5 M}

  • B.

    πσ0B0R23M\frac{\pi \sigma_0 B_0 R^2}{3 M}

  • C.

    πσ0B0R25M\frac{\pi \sigma_0 B_0 R^2}{5 M}

  • D.

    πσ0B0R22M\frac{\pi \sigma_0 B_0 R^2}{2 M}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Current Density Vector|Gyroscopic Stability|Lorentz Force Vector Direction|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the limits of the gyromagnetic ratio shortcut and the application of gyroscopic precession.

A common trap for students is to blindly apply the gyromagnetic ratio μ⃗=Q2ML⃗\vec{\mu} = \frac{Q}{2M}\vec{L}, which is only valid when the charge-to-mass ratio is spatially uniform.

In this setup, the mass density is uniform, but the charge density varies linearly with the radius.

If a student calculates the total charge Q=23πσ0R2Q = \frac{2}{3}\pi\sigma_0 R^2 and uses the ratio, they will incorrectly arrive at a precession rate of πσ0B0R23M\frac{\pi \sigma_0 B_0 R^2}{3 M}.

The correct physical approach requires integrating the Lorentz force density (or the elemental magnetic moments) explicitly to find the true magnetic torque, and then equating it to the gyroscopic rate of change of angular momentum Ω⃗p×L⃗\vec{\Omega}_p \times \vec{L}.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptCurrent Density Vector
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree