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Question #42734
The Question
Consider a Cartesian coordinate system where the -axis is vertically upwards. A fixed, infinitely long straight wire lies along the -axis and carries a constant current in the direction. A straight conducting rod of mass and length is suspended by two massless, rigid, non-conducting rods of length from the -axis. The rod is always parallel to the -axis and is free to swing as a pendulum in the -plane. A uniform external magnetic field is present in the region. The swinging rod is part of a closed electrical circuit containing a resistor, with the rest of the circuit arranged such that it does not experience any magnetic force or contribute to the motional EMF. The resistor has a color code: Brown, Black, Silver, Gold. At a certain instant, the pendulum passes through its lowest point (on the negative -axis) with an angular velocity , moving in the direction. Calculate the total tension in the two suspending rods at this instant. (Take and . Ignore the self-inductance of the circuit.)
Options
- A.
0.15 \text{ N}
- B.
0.20 \text{ N}
- C.
0.10 \text{ N}
- D.
0.145 \text{ N}
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Color Code Logic|Force Between Parallel Conductors|Non-Uniform Circular Motion|Vector Cross-Product
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of motional EMF, color-code resistance, and the magnetic force between parallel conductors within a non-uniform circular motion context.
The primary trap lies in the free-body diagram at the lowest point.
Students often correctly identify the centripetal force requirement () and gravity, but overlook or misdirect the varying Lorentz force () generated by the induced current interacting with the fixed wire's magnetic field.
Because the induced current's direction depends on the velocity vector (), it creates a parallel current scenario resulting in an attractive upward force.
Failing to account for this force, or incorrectly assuming it is repulsive, leads to erroneous tension calculations.
Additionally, misinterpreting the Silver multiplier in the color code leads to a cascading error in the current and force magnitude.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Current Electricity - Class 12 |
| Concept | Color Code Logic |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |