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Question #42850

Difficulty: 8/10 | 🟢 Free

The Question

A high-frequency periodic thermal source generates a temperature wave in a semi-infinite rod (Rod 1). The wave travels towards a junction at x=0x=0 where Rod 1 is perfectly joined to another semi-infinite rod (Rod 2). The amplitude of the incident temperature wave at the junction is T0=60 KT_0 = 60 \text{ K}. At the junction, both the temperature and the total heat current are continuous. The properties of the rods are given as:

Rod 1: Cross-sectional area A1=AA_1 = A, thermal conductivity κ1=2κ\kappa_1 = 2\kappa, volumetric heat capacity (ρc)1=5C(\rho c)_1 = 5C. Rod 2: Cross-sectional area A2=2AA_2 = 2A, thermal conductivity κ2=5κ\kappa_2 = 5\kappa, volumetric heat capacity (ρc)2=8C(\rho c)_2 = 8C.

Assuming the thermal wave propagates as T(x,t)∝e−γxcos⁡(ωt−γx)T(x,t) \propto e^{-\gamma x} \cos(\omega t - \gamma x) where γ=ωρc/2κ\gamma = \sqrt{\omega \rho c / 2\kappa}, what is the amplitude of the transmitted temperature wave in Rod 2 at the junction?

Options

  • A.

    24 \text{ K}

  • B.

    20 \text{ K}

  • C.

    40 \text{ K}

  • D.

    36 \text{ K}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Boundary Condition Reflection|Thermal Conductivity in Series and Parallel|Small Angle Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between steady-state heat conduction and transient thermal wave propagation.

In steady-state problems, students correctly use static thermal conductance K=κAK = \kappa A to evaluate heat flow.

However, for a high-frequency thermal wave, the spatial derivative of the temperature profile introduces the wave vector γ\gamma, which depends on the thermal diffusivity.

Consequently, the dynamic thermal impedance (or effusivity) governing wave reflection and transmission depends on AρcκA\sqrt{\rho c \kappa}.

Students who mistakenly apply the static conductance ratio will choose 20 K, while those who ignore the cross-sectional area mismatch will choose 40 K.

Calculating the reflected amplitude instead of the transmitted one leads to 36 K.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptBoundary Condition Reflection
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree