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Question #42857

Difficulty: 8/10 | 🟢 Free

The Question

A uniform wire of unstretched length L0L_0, cross-sectional area A0A_0, mass mm, and coefficient of linear expansion α\alpha is suspended vertically from a rigid support. A block of mass MM (M≫mM \gg m) is attached to its lower end. A vibrator at the top end drives the wire at a constant frequency ff, forming a standing wave. The nn-th node from the top is at a distance xnx_n (Assume the top end acts as a node). If the temperature of the wire is increased by ΔT\Delta T, the fractional change in the position of the nn-th node, Δxnxn\frac{\Delta x_n}{x_n}, is given by: (Assume αΔT≪1\alpha \Delta T \ll 1, initial stress σ=MgA0≪Y\sigma = \frac{Mg}{A_0} \ll Y, where YY is the Young's modulus of the wire)

Options

  • A.

    12αΔT(1−2σY)\frac{1}{2} \alpha \Delta T \left( 1 - \frac{2\sigma}{Y} \right)

  • B.

    12αΔT(1−σY)\frac{1}{2} \alpha \Delta T \left( 1 - \frac{\sigma}{Y} \right)

  • C.

    αΔT(1−2σY)\alpha \Delta T \left( 1 - \frac{2\sigma}{Y} \right)

  • D.

    12αΔT\frac{1}{2} \alpha \Delta T

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Standing Wave Nodes/Antinodes|Thermal Expansion of Area and Volume|Calculus (Chain Rule)

Why This Question Is Tricky

Common Mistakes

This question tests the coupled effects of thermal expansion and elasticity on wave propagation.

The primary trap is assuming that thermal expansion only affects the unstretched length, leading to the naive answer 12αΔT\frac{1}{2}\alpha\Delta T.

Students often fail to account for the fact that as the wire expands thermally, its cross-sectional area increases (A=A0(1+2αΔT)A = A_0(1+2\alpha\Delta T)), which decreases the elastic stretch for a constant tension.

Furthermore, students might incorrectly assume μ\mu is constant or use unstressed density, missing that μ=m/L\mu = m/L dynamically couples the wave speed to the total stretched length.

Differentiating the full thermo-elastic length equation is required to capture the (1−2σ/Y)(1 - 2\sigma/Y) correction factor.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptStanding Wave Nodes/Antinodes
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree