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Question #42869
The Question
Two harmonic signals of frequencies and () are fed into a phase detector. At , the signals are perfectly in phase. The phase detector outputs a voltage , where is the instantaneous phase difference between the signals, is the calibration constant, and is a systematic zero-error (DC offset). A student wishes to determine the beat frequency . They calculate the ideal target voltage that corresponds to exactly beats, assuming no zero-error. The student then measures the time it takes for the actual output voltage to reach this calculated from . Using the measured time , the student calculates the apparent beat frequency as and finds it to be . What is the true beat frequency ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Beats and Frequency Difference|Zero Error Correction in Instruments|Superposition Principle
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to correctly propagate a systematic zero-error through a non-linear measurement process involving wave superposition and phase difference.
Students often fall into the trap of applying the zero-error correction directly to the final calculated frequency (e.g., assuming an additive or subtractive frequency shift) rather than incorporating it into the time-domain phase equation.
By setting a fixed voltage threshold, the zero-offset alters the time required to reach the target phase, making the relationship between the measured and true beat frequency multiplicative () rather than simply additive.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Waves - Class 11 Part 2 |
| Concept | Beats and Frequency Difference |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |