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Question #42871

Difficulty: 8/10 | 🟢 Free

The Question

In a modified Young's Double Slit Experiment, a monochromatic light of vacuum wavelength λ\lambda is incident on two narrow slits S1S_1 and S2S_2 separated by a distance dd. A screen is placed at a distance DD (D≫dD \gg d) from the slits. The region between the slits and the screen is filled with a transparent medium whose refractive index varies linearly along the transverse direction yy (parallel to the screen and perpendicular to the slits) as n(y)=n0+αyn(y) = n_0 + \alpha y, where n0n_0 and α\alpha are positive constants. The origin y=0y=0 is on the central axis equidistant from the slits, with S1S_1 at y=d/2y = d/2 and S2S_2 at y=−d/2y = -d/2. Assuming that light rays travel in straight lines from the slits to the screen and d≪y≪Dd \ll y \ll D, which of the following expressions gives the local fringe width β(y)\beta(y) at a coordinate yy on the screen?

Options

  • A.

    λDd(n0+αy)\frac{\lambda D}{d(n_0 + \alpha y)}

  • B.

    λDd(n0+αy2)\frac{\lambda D}{d(n_0 + \frac{\alpha y}{2})}

  • C.

    λDdn0\frac{\lambda D}{d n_0}

  • D.

    λDd(n0+2αy)\frac{\lambda D}{d(n_0 + 2\alpha y)}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Beats and Frequency Difference|Fringe Width Invariance|Medium Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to transition from the standard constant-phase YDSE model to a differential phase-gradient model.

The primary trap is the 'Fringe Width Invariance' misconception, where students assume β=λD/(nlocald)\beta = \lambda D / (n_{local} d) and simply substitute the local refractive index at the screen n(y)=n0+αyn(y) = n_0 + \alpha y (leading to Option A), or assume the fringe width remains constant based on the central refractive index n0n_0 (Option C).

By forcing the integration of the refractive index gradient along the optical path, the problem reveals that the spatial 'beats' (fringes) are chirped, and the effective refractive index governing the local fringe spacing is the path-averaged gradient n0+αy/2n_0 + \alpha y / 2, not the point-value at the screen.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptBeats and Frequency Difference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree