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Question #42878

Difficulty: 8/10 | 🟢 Free

The Question

A monochromatic laser beam of initial intensity I0I_0 (in W m−2\text{W m}^{-2}) propagates along the positive xx-axis into a thick semiconductor crystal starting at x=0x=0. As the beam propagates, photon absorption increases the local temperature of the crystal, which in turn decreases the energy band gap. Assume the local steady-state temperature rise is directly proportional to the local beam intensity I(x)I(x), such that the effective absorption coefficient becomes α(I)=α0+λI(x)\alpha(I) = \alpha_0 + \lambda I(x). Here, α0\alpha_0 (in m−1\text{m}^{-1}) is the intrinsic absorption coefficient and λ\lambda (in m W−1\text{m W}^{-1}) is a positive thermal-coupling constant. Determine the depth x1/2x_{1/2} (in m\text{m}) at which the beam intensity drops to half of its initial value (I0/2I_0/2).

Options

  • A.

    1α0ln⁡(2α0+λI0α0+λI0)\frac{1}{\alpha_0} \ln \left( \frac{2\alpha_0 + \lambda I_0}{\alpha_0 + \lambda I_0} \right)

  • B.

    1α0ln⁡(2)\frac{1}{\alpha_0} \ln (2)

  • C.

    1α0+λI0ln⁡(2)\frac{1}{\alpha_0 + \lambda I_0} \ln (2)

  • D.

    1α0ln⁡(2α0+2λI0α0+λI0)\frac{1}{\alpha_0} \ln \left( \frac{2\alpha_0 + 2\lambda I_0}{\alpha_0 + \lambda I_0} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Wave Intensity and Medium|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Common Mistakes

Students often memorize the Beer-Lambert law I(x)=I0e−αxI(x) = I_0 e^{-\alpha x} and treat the absorption coefficient α\alpha as a strict material constant.

When faced with a temperature-dependent bandgap (Varshni effect) where local heating is proportional to intensity, they might incorrectly evaluate α\alpha at the incident surface (α=α0+λI0\alpha = \alpha_0 + \lambda I_0) and treat it as a constant for the entire propagation, leading to the incorrect Option C.

Alternatively, they might ignore the intensity dependence entirely, leading to Option B.

The correct physical approach recognizes α\alpha as a state function of local intensity α(I)\alpha(I), requiring the formulation and integration of a non-linear differential equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptWave Intensity and Medium
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree