Start Learning Free

Before You Begin

Question #42889

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge q=Neq = Ne (where NN is a positive integer and ee is the elementary charge) is accelerated from rest through a potential difference VV. It then enters a vacuum chamber containing a cylindrically symmetric magnetic field given by B⃗=αrk^\vec{B} = \frac{\alpha}{r} \hat{k}, where rr is the radial distance from the zz-axis and α\alpha is a positive constant. The particle moves in a stable circular orbit of radius RR in the xyxy-plane, centered at the origin.

Assume the particle's orbit satisfies the Bohr-Sommerfeld quantization condition, meaning the circumference of the orbit is an integer multiple kk (k=1,2,3,…k = 1, 2, 3, \dots) of the particle's de Broglie wavelength. Which of the following pairs (V,R)(V, R) correctly gives the required accelerating potential and the allowed orbital radii?

Options

  • A.

    (Neα22m,kℏNeα)\left( \frac{N e \alpha^2}{2m}, \frac{k \hbar}{N e \alpha} \right)

  • B.

    (keα22m,Nℏkeα)\left( \frac{k e \alpha^2}{2m}, \frac{N \hbar}{k e \alpha} \right)

  • C.

    (N2eα22m,kℏeα)\left( \frac{N^2 e \alpha^2}{2m}, \frac{k \hbar}{e \alpha} \right)

  • D.

    (Neα2m,kℏ2Neα)\left( \frac{N e \alpha^2}{m}, \frac{k \hbar}{2 N e \alpha} \right)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Quantization of Charge|De Broglie Wavelength Scaling|Trajectory of Charged Particle

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of classical electrodynamics and semiclassical quantum mechanics.

In a 1/r1/r magnetic field, the Lorentz force dictates that the momentum required for a circular orbit is strictly constant (p=qαp = q\alpha), regardless of the radius.

Consequently, the classical radius is arbitrary (neutral equilibrium), and the accelerating potential VV depends only on the charge quantization NN, not on the orbital radius.

Students typically fall into the trap of blindly applying the uniform magnetic field formula (R=mv/qBR = mv/qB), incorrectly assuming that the accelerating potential must be quantized with the quantum number kk or depend on RR.

The problem forces students to realize that VV acts only as a velocity selector, while the Bohr-Sommerfeld condition independently discretizes the allowed radii.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptQuantization of Charge
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree