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Question #42897

Difficulty: 8/10 | 🟢 Free

The Question

Three point charges are fixed on a circle of radius RR in the xyxy-plane centered at the origin. Charge q1=+qq_1 = +q is located at θ=0∘\theta = 0^\circ, q2=−qq_2 = -q is at θ=60∘\theta = 60^\circ, and q3=+qq_3 = +q is at θ=120∘\theta = 120^\circ. An ideal electric dipole with dipole moment p⃗=p0i^\vec{p} = p_0 \hat{i} is placed at the origin. What is the magnitude of the net electric force experienced by the dipole?

Options

  • A.

    43qp08πϵ0R3\frac{\sqrt{43} q p_0}{8 \pi \epsilon_0 R^3}

  • B.

    00

  • C.

    5qp08πϵ0R3\frac{5 q p_0}{8 \pi \epsilon_0 R^3}

  • D.

    37qp08πϵ0R3\frac{3\sqrt{7} q p_0}{8 \pi \epsilon_0 R^3}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Superposition Principle|Conservative Force Field|Vector Decomposition Ambiguity

Why This Question Is Tricky

Common Mistakes

This question weaponizes 'symmetry bias' by placing charges such that the net electric field at the origin is exactly zero.

Students relying on superficial symmetry will incorrectly conclude that a zero field implies zero force on the dipole (Option B).

However, the force on an ideal dipole depends on the gradient of the electric field (F⃗=(p⃗⋅∇)E⃗\vec{F} = (\vec{p} \cdot \nabla)\vec{E}), not the field itself.

Furthermore, the problem forces rigorous vector decomposition of the field gradients.

A secondary trap awaits students who attempt the gradient calculation but incorrectly assume that the anti-symmetric signs of q2q_2 and q3q_3 cause their gradient components to symmetrically cancel, leading to Option C.

The non-orthogonal 60∘/120∘60^\circ/120^\circ configuration ensures that standard shortcut vectors fail, demanding component-wise superposition.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptSuperposition Principle
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree