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Question #42958
The Question
An AC voltage source is connected in series with a capacitor of capacitance and an inductor of inductance having a ferromagnetic core. The ohmic resistance of the entire circuit is negligible. Due to hysteresis, the ferromagnetic core dissipates an energy per cycle, where is a positive constant with appropriate SI units and is the root-mean-square current. The angular frequency of the source is continuously varied. It is observed that for a specific fixed value of , the current amplitude in the circuit attains its maximum possible value exactly at the angular frequency . Which of the following expressions correctly gives the required capacitance ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Hysteresis Loop Area|Average Power over Cycle|Capacitive Reactance Dependency
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to integrate macroscopic thermodynamic losses (hysteresis) with AC circuit theory.
The primary trap is treating the resonance condition as simply (yielding ), which is only valid when the circuit resistance is independent of frequency.
By modeling the hysteresis energy loss per cycle, students must deduce that the effective resistance scales linearly with frequency ().
Consequently, the total impedance has a frequency-dependent resistive term that shifts the minimum of .
Students must construct the full impedance function and differentiate it with respect to to find the true condition for maximum current amplitude, preventing a simple static calculation.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Magnetism and Matter - Class 12 |
| Concept | Hysteresis Loop Area |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |