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Question #42963

Difficulty: 8/10 | 🟢 Free

The Question

A small solid diamagnetic sphere of mass MM and volume VV is attached to one end of a massless rigid rod of length LL. The other end of the rod is pivoted at the origin OO, allowing the sphere to rotate freely in the xyxy-plane. The system is placed in a static, non-uniform magnetic field given by B⃗=B0(1+αx)i^−B0αyj^\vec{B} = B_0 (1 + \alpha x) \hat{i} - B_0 \alpha y \hat{j}, where B0B_0 and α\alpha are positive constants. The induced magnetic dipole moment of the sphere is m⃗=−χVμ0B⃗\vec{m} = -\frac{\chi V}{\mu_0} \vec{B}, where χ>0\chi > 0 is the magnitude of its diamagnetic susceptibility. If the sphere is projected from the position (L,0)(L, 0) with an initial angular velocity ω0k^\omega_0 \hat{k}, what is its angular velocity ω\omega when it crosses the position (−L,0)(-L, 0)? Assume no gravity and no other resistive forces.

Options

  • A.

    ω02+4χVB02αμ0ML\sqrt{\omega_0^2 + \frac{4\chi V B_0^2 \alpha}{\mu_0 M L}}

  • B.

    ω02+8χVB02αμ0ML\sqrt{\omega_0^2 + \frac{8\chi V B_0^2 \alpha}{\mu_0 M L}}

  • C.

    ω02−4χVB02αμ0ML\sqrt{\omega_0^2 - \frac{4\chi V B_0^2 \alpha}{\mu_0 M L}}

  • D.

    ω02+2χVB02αμ0ML\sqrt{\omega_0^2 + \frac{2\chi V B_0^2 \alpha}{\mu_0 M L}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Diamagnetic Property of Materials|Non-Uniform Circular Motion|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize rigid body dynamics with the energetics of induced magnetic dipoles in non-uniform fields.

The primary 'Lethal Trap' lies in the potential energy formulation.

Students frequently misapply the potential energy formula for a permanent dipole (U=−m⃗⋅B⃗U = -\vec{m} \cdot \vec{B}) to an induced dipole.

For an induced dipole, the magnetic moment is proportional to the field (m⃗∝B⃗\vec{m} \propto \vec{B}), meaning the work done to establish the dipole moment must be accounted for, introducing a crucial factor of 1/21/2 (U=−12m⃗⋅B⃗U = -\frac{1}{2}\vec{m} \cdot \vec{B}).

Failing to recognize this distinction leads directly to Option B.

Additionally, students must correctly evaluate the spatial gradient of B2B^2 along the constrained circular trajectory rather than mistakenly integrating a 1D force, testing their vector calculus application in non-uniform circular motion.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptDiamagnetic Property of Materials
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree