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Question #42997

Difficulty: 8/10 | 🟢 Free

The Question

A long straight wire and a coplanar square loop of side aa lie on a smooth horizontal table. The wire carries a time-varying current I(t)=I0(1+αt)I(t) = I_0(1 + \alpha t), where I0I_0 and α\alpha are positive constants. At time t=0t = 0, the near edge of the loop is parallel to the wire and at a distance aa from it. If the loop is being pulled away from the wire with a constant velocity vv perpendicular to the wire, which of the following expressions represents the magnitude of the total induced electromotive force (EMF) in the loop at t=0t = 0?

Options

  • A.

    μ0I02π∣aαln⁡2−v2∣\frac{\mu_0 I_0}{2\pi} \left| a \alpha \ln 2 - \frac{v}{2} \right|

  • B.

    μ0I02π(aαln⁡2+v2)\frac{\mu_0 I_0}{2\pi} \left( a \alpha \ln 2 + \frac{v}{2} \right)

  • C.

    μ0I0aα2πln⁡2\frac{\mu_0 I_0 a \alpha}{2\pi} \ln 2

  • D.

    μ0I0v4π\frac{\mu_0 I_0 v}{4\pi}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Mutual Inductance Reciprocity|Motional EMF|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply Faraday's Law in its complete form for a system where both the magnetic field source (current) and the geometry (position) are time-dependent.

A common trap is to blindly apply the static mutual inductance formula ε=−Mdidt\varepsilon = -M \frac{di}{dt}, completely ignoring the motional EMF generated by the loop translating through a spatially varying magnetic field.

Conversely, students might only calculate the motional EMF ∫(v⃗×B⃗)⋅dl⃗\int (\vec{v} \times \vec{B}) \cdot d\vec{l} and forget the transformer EMF.

By requiring the full expansion of the flux derivative dΦdt=M(t)dIdt+I(t)dMdt\frac{d\Phi}{dt} = M(t)\frac{dI}{dt} + I(t)\frac{dM}{dt}, the problem forces the synthesis of both transformer and motional EMFs, while also testing the correct relative sign (Lenz's Law) between the two competing effects.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptMutual Inductance Reciprocity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree