Start Learning Free

Before You Begin

Question #43006

Difficulty: 8/10 | 🟢 Free

The Question

A proton of mass mm and charge qq enters a region of non-uniform static magnetic field. At the origin (z=0z=0), the magnetic field is B⃗=B0k^\vec{B} = B_0 \hat{k} and the proton has a velocity v⃗=v0cos⁡(30∘)k^+v0sin⁡(30∘)i^\vec{v} = v_0 \cos(30^\circ) \hat{k} + v_0 \sin(30^\circ) \hat{i}. The magnetic field points primarily in the +z+z direction, and its magnitude slowly increases along the zz-axis. Assume the spatial variation of the magnetic field is gradual enough that the magnetic moment μ=mv⊥22B\mu = \frac{m v_{\perp}^2}{2B} remains an adiabatic invariant. Find the ratio of the local pitch of the proton's helical path at z=0z=0 to its local pitch at a point where the magnetic field magnitude becomes 2B02B_0. (The local pitch is defined as p=v∥Tp = v_{\parallel} T, where v∥v_{\parallel} is the longitudinal velocity and TT is the local time period of gyration).

Options

  • A.

    6\sqrt{6}

  • B.

    22

  • C.

    32\sqrt{\frac{3}{2}}

  • D.

    222\sqrt{2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Trajectory of Charged Particle|Moving Charge in Non-Uniform B|Centripetal Acceleration Vector

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of charged particle dynamics in a spatially varying magnetic field (the magnetic mirror effect).

The primary trap is the assumption that the longitudinal velocity v∥v_{\parallel} remains constant because the primary magnetic field is in the z-direction.

Students often incorrectly recall that F⃗=q(v⃗×B⃗)\vec{F} = q(\vec{v} \times \vec{B}) for B⃗=Bk^\vec{B} = B\hat{k} yields zero force in the z-direction.

However, a spatially varying field B⃗\vec{B} must have a radial component to satisfy Gauss's Law for Magnetism (∇⋅B⃗=0\nabla \cdot \vec{B} = 0).

This radial component produces a z-directed Lorentz force that decelerates the particle axially.

By failing to apply energy conservation alongside the adiabatic invariant, students incorrectly use v∥=v∥0v_{\parallel} = v_{\parallel 0}, leading to the trap answer of 2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptTrajectory of Charged Particle
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree