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Question #43015

Difficulty: 8/10 | 🟢 Free

The Question

A long, straight, thick cylindrical conductor of radius RR carries a steady DC current. The current density inside this main conductor varies radially as J(r)=J0(1−rR)J(r) = J_0 \left(1 - \frac{r}{R}\right), where rr is the distance from the central axis and J0J_0 is a positive constant. At a certain junction, this main conductor splits into 44 identical, long, straight cylindrical branches, each of radius R2\frac{R}{2}. After a sufficient distance from the junction, the current in each branch redistributes such that its current density becomes uniform across its cross-section. Let B1B_1 be the magnitude of the magnetic field inside the main conductor at a radial distance r=R2r = \frac{R}{2} from its axis. Let B2B_2 be the magnitude of the magnetic field inside one of the branches at a radial distance r′=R4r' = \frac{R}{4} from its own central axis. Find the ratio B1B2\frac{B_1}{B_2}.

Options

  • A.

    4

  • B.

    2

  • C.

    43\frac{4}{3}

  • D.

    8

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Ampere’s Circuital Law Symmetry|Kirchhoff’s Junction Rule|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the application of Ampere's Circuital Law across a junction with changing current density profiles.

The primary trap lies in the assumption of profile conservation; students often incorrectly assume that the non-uniform current density profile J(r)J(r) of the main conductor maps directly into the branches (i.e., J′(r′)=J0(1−r′/(R/2))J'(r') = J_0(1 - r'/(R/2))), rather than using Kirchhoff's Junction Rule to find the total branch current and then applying the new uniform boundary condition.

Additionally, students may fail to properly integrate the non-uniform J(r)J(r) to find the enclosed current, instead relying on the invalid I=JAI = J A formula.

This highlights the critical difference between total flux/current conservation and the local redistribution of current density vectors at a boundary.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptAmpere’s Circuital Law Symmetry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree