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Question #43038

Difficulty: 8/10 | 🟢 Free

The Question

A cylindrical shunt resistor of radius aa (in m\text{m}), length ll (in m\text{m}), electrical conductivity σ\sigma (in S/m\text{S/m}), and electrical permittivity ϵ\epsilon (in F/m\text{F/m}) is connected across an AC voltage source V(t)=V0sin⁡(ωt)V(t) = V_0 \sin(\omega t), where V0V_0 is the voltage amplitude (in V\text{V}) and ω\omega is the angular frequency (in rad/s\text{rad/s}). Assuming the electric field is uniform throughout the volume of the resistor and edge effects are negligible, what is the maximum instantaneous magnitude of the Poynting vector, SmaxS_{max} (in W/m2\text{W/m}^2), evaluated at the curved surface of the cylinder?

Options

  • A.

    aV024l2(σ+σ2+(ϵω)2)\frac{a V_0^2}{4 l^2} \left( \sigma + \sqrt{\sigma^2 + (\epsilon \omega)^2} \right)

  • B.

    aV022l2σ2+(ϵω)2\frac{a V_0^2}{2 l^2} \sqrt{\sigma^2 + (\epsilon \omega)^2}

  • C.

    aσV022l2\frac{a \sigma V_0^2}{2 l^2}

  • D.

    aV024l2(σ+ϵω)\frac{a V_0^2}{4 l^2} \left( \sigma + \epsilon \omega \right)

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Shunt Resistance Conversion|Ampere’s Law Displacement Current|Poynting Vector and Intensity

Why This Question Is Tricky

Common Mistakes

This question tests the transition from lumped-element circuit theory to Maxwell's field theory in high-frequency regimes.

Students commonly fall into the 'Ohmic Fallacy' by ignoring the displacement current (ϵ∂E/∂t\epsilon \partial E/\partial t) inside the resistor, leading to Option C.

Another severe trap is assuming that the maximum of the Poynting vector is simply the product of the maximum electric and magnetic fields (Smax=EmaxBmax/μ0S_{max} = E_{max}B_{max}/\mu_0), which leads to Option B.

This ignores the crucial phase difference between the conduction current (in phase with EE) and the displacement current (in quadrature with EE).

The correct approach requires evaluating the instantaneous cross product E⃗×B⃗\vec{E} \times \vec{B} and maximizing the resulting time-dependent function.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptShunt Resistance Conversion
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree