Before You Begin
Question #43052
The Question
A beam of non-relativistic electrons, each of mass and initial kinetic energy , is incident on a double-slit apparatus with slit separation . A screen is placed at a distance from the slits (). In the region between the slits and the screen, a uniform electric field is applied perpendicular to the plane of the slits. This field accelerates the electrons such that their kinetic energy upon reaching the screen is . If is the initial de Broglie wavelength of the electrons before entering the slits, what is the fringe width of the interference pattern formed on the screen? (Assume the small-angle approximation holds and ignore gravitational effects).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Optical Path Difference|De Broglie Wavelength Scaling|Small Angle Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the validity of the standard Young's Double Slit Experiment (YDSE) formula in a region with a spatially varying potential.
Students commonly fall into the trap of assuming they can use the initial wavelength (Option A), the arithmetic average of the initial and final wavelengths (Option B), or the wavelength corresponding to the average kinetic energy (Option C).
The rigorous physical approach requires calculating the phase accumulation via the action integral along the classical parabolic trajectory.
The effective momentum that dictates the interference pattern is derived from the spatial integral of the inverse momentum, which surprisingly yields the arithmetic mean of the initial and final momenta for a uniform field, leading to a non-intuitive fractional coefficient.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Wave Optics - Class 12 |
| Concept | Optical Path Difference |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |