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Question #43054
The Question
In a Young's Double Slit Experiment, light of wavelength illuminates two slits separated by an initial distance . The interference pattern is recorded on a photographic plate placed at a distance (). During the exposure time , the plane containing the slits is uniformly heated such that the slit separation increases linearly with time, reaching a final separation of . The plate records the time-averaged intensity , where is the distance from the central maximum. What is the minimum non-zero distance where the fringe contrast completely vanishes?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Optical Path Difference|Fringe Width Invariance|Linear Expansion
Why This Question Is Tricky
Common Mistakes
This question tests the distinction between discrete superposition and continuous time-averaging in wave optics.
A common trap is assuming that a spatial shift corresponding to half a fringe width (a phase shift of ) causes complete blurring, as it does when superimposing two discrete static patterns.
Consequently, students incorrectly set , leading to the trap answer .
However, for a continuously expanding slit separation, a phase sweep of only reduces the contrast (yielding an amplitude factor of ).
Complete vanishing of the fringe contrast requires the time-average integral to cover exactly one full period of the cosine function, meaning the phase must sweep through .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Wave Optics - Class 12 |
| Concept | Optical Path Difference |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |