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Question #43078

Difficulty: 8/10 | 🟢 Free

The Question

A real transformer is modeled as an ideal transformer with a primary-to-secondary turns ratio of N1:N2=1:2N_1 : N_2 = 1 : 2, in series with a secondary leakage inductance Ll=20 mHL_l = 20 \text{ mH}. The primary winding is driven by an AC voltage source V1(t)=100sin⁡(ωt) VV_1(t) = 100 \sin(\omega t) \text{ V}. The secondary terminals of the transformer are connected to a load consisting of a resistor R=50 ΩR = 50 \ \Omega and a capacitor C=50 μFC = 50 \ \mu\text{F} in series. The angular frequency ω\omega of the source is adjusted such that the secondary current I2(t)I_2(t) is exactly 180∘180^\circ out of phase with the primary voltage V1(t)V_1(t). Calculate the peak voltage across the secondary terminals of the transformer at this frequency.

Options

  • A.

    4029 V40\sqrt{29} \text{ V}

  • B.

    200 V200 \text{ V}

  • C.

    120 V120 \text{ V}

  • D.

    280 V280 \text{ V}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Transformer Flux Linkage|Frequency Sensitivity of Z|Bandwidth in RLC

Why This Question Is Tricky

Common Mistakes

This question tests the transition from an ideal transformer model to a real-world AC circuit model.

Students commonly fall into the trap of assuming Vterminal=(N2/N1)V1=200 VV_{terminal} = (N_2/N_1)V_1 = 200 \text{ V} (Option B), ignoring the internal voltage drop across the leakage inductance.

Furthermore, even if they identify the resonance condition required for the 180∘180^\circ phase shift, they often mistakenly assume that because the reactive components 'cancel out' for the total circuit, the terminal voltage is simply the voltage across the resistor.

They fail to recognize that the leakage inductance is internal to the transformer, meaning the accessible terminal voltage is the phasor sum of the resistive and capacitive voltage drops, which actually exceeds the ideal induced EMF due to the capacitive nature of the load.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptTransformer Flux Linkage
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree