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Question #43087

Difficulty: 8/10 | 🟢 Free

The Question

A parallel-plate capacitor consists of two circular plates of radius RR separated by a very small vacuum gap dd (d≪Rd \ll R). The plates are initially uncharged. Starting at t=0t=0, a radial surface current flows inward on the positive plate (located at z=0z=0) and outward on the negative plate (located at z=dz=d). The surface current density on the positive plate is given by K⃗(r,t)=−βr2tr^\vec{K}(r,t) = - \beta r^2 t \hat{r}, where β\beta is a positive constant, rr is the radial distance from the center, and r^\hat{r} is the outward radial unit vector. Assuming edge effects are negligible, what is the magnitude of the magnetic field BB at a radial distance rr (r<Rr < R) inside the gap between the plates?

Options

  • A.

    μ0βtr2\mu_0 \beta t r^2

  • B.

    23μ0βtr2\frac{2}{3} \mu_0 \beta t r^2

  • C.

    32μ0βtr2\frac{3}{2} \mu_0 \beta t r^2

  • D.

    12μ0βtr2\frac{1}{2} \mu_0 \beta t r^2

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Maxwell's Correction to Ampere's Law|Current Density Vector|Differential Calculus

Why This Question Is Tricky

Common Mistakes

This problem tests the rigorous application of the Ampere-Maxwell law alongside the local continuity equation for a non-uniform system.

A common lethal trap is misapplying Gauss's law by assuming E=Qenc/(ϵ0πr2)E = Q_{enc}/(\epsilon_0 \pi r^2), which incorrectly treats the electric field as uniform over the disk, or miscalculating the divergence of the surface current by omitting the 1/r1/r cylindrical geometric factor (assuming ∇⋅K⃗=∂Kr/∂r\nabla \cdot \vec{K} = \partial K_r/\partial r).

Both errors lead to an incorrect displacement current density of 2βrt2\beta r t instead of the true 3βrt3\beta r t, resulting in the trap option 23μ0βtr2\frac{2}{3} \mu_0 \beta t r^2.

Students must recognize that for a parallel-plate capacitor (d≪Rd \ll R), the electric field is determined strictly by the local surface charge density (E=σ/ϵ0E = \sigma/\epsilon_0), forcing them to correctly derive σ(r,t)\sigma(r,t) via the full 2D divergence operator before closing the Amperean loop.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Waves - Class 12
ConceptMaxwell's Correction to Ampere's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree