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Question #43096
The Question
A small circular loop of radius is placed at the origin in the -plane and carries an alternating current . This loop acts as an oscillating magnetic dipole. Consider a point in the -plane at a distance from the origin (). The displacement current density at point due to the electromagnetic fields of the dipole can be expressed in the form , where is the azimuthal unit vector, is a time-independent scalar amplitude, and is the phase difference relative to the source current . Given that the speed of light in vacuum is , which of the following expressions correctly represents the phase difference ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Phase Relationship|Displacement Current Source|Magnetic Dipole Moment of Revolving Electron
Why This Question Is Tricky
Common Mistakes
This question targets the 'Near-Field Approximation' fallacy and tests the student's understanding of retarded potentials in electrodynamics.
Students often incorrectly assume that the magnetic field of an oscillating dipole is simply the instantaneous Biot-Savart field, which would lead to a phase difference of zero (ignoring retardation entirely).
Even if they account for the time delay , they might erroneously isolate either the radiation () term or the quasi-static () term.
By asking for the displacement current phase at an arbitrary distance , the student is forced to use the complete retarded vector potential.
The phase shift arises directly from the superposition of these near-field and far-field components, proving that phase synchronization is distance-dependent and that Maxwell's equations do not permit action-at-a-distance.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Waves - Class 12 |
| Concept | Phase Relationship |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |