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Question #43139
The Question
A transparent optical slab of thickness occupies the region . The slab contains a uniform negative volume charge density (where ). The boundary surfaces at and are maintained at a constant positive electrostatic potential . The refractive index of the slab material is directly proportional to the local electrostatic potential , such that where is a positive constant. A light ray enters the slab at the origin from a medium of refractive index , making an angle with the -axis. Which of the following expressions gives the minimum value of required so that the light ray does not cross the mid-plane () of the slab?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Prism Minimum Deviation|Continuous Charge Distribution|Calculus
Why This Question Is Tricky
Common Mistakes
This problem tests the synthesis of electrostatics (Poisson's equation for continuous charge distributions) and optics (Fermat's principle in a gradient-index medium).
The continuous variation of the refractive index mimics the effective potential in a gravitational field (time dilation analogy), where light rays bend towards regions of higher refractive index.
A common trap is misapplying Gauss's law to find the potential difference, incorrectly assuming a uniform electric field or forgetting the spatial integration constants, which leads to an incorrect factor of 4 instead of 8 in the potential well depth (Option B).
Furthermore, students often fail to recognize that in a continuously stratified medium, Snell's law generalizes to , and instead attempt to use discrete boundary formulas or confuse the normal angle with the grazing angle (Option C).
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Ray Optics and Optical Instruments - Class 12 |
| Concept | Prism Minimum Deviation |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |